SQL实现split函数,自定义分割字符,自定义取出第几个分割字符前的字符串
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-SQL
CREATE FUNCTION [dbo].[split]
(@str nvarchar(4000),@code varchar(10),@no int )
RETURNS varchar(200)
AS
BEGIN
declare @intLen int
declare @count int
declare @indexb int
declare @indexe int
set @intLen=len(@code)
set @count=0
set @indexb=1
if @no=0
if charindex(@code,@str,@indexb)<>0
return left(@str,charindex(@code,@str,@indexb)-1)
else
return @str
while charindex(@code,@str,@indexb)<>0
begin
set @count=@count+1
if @count=@no
break
set @indexb=@intLen+charindex(@code,@str,@indexb)
end
if @count=@no
begin
set @indexe=@intLen+charindex(@code,@str,@indexb)
if charindex(@code,@str,@indexe)<>0
return substring(@str,charindex(@code,@str,@indexb)+len(@code),charindex(@code,@str,@indexe)-charindex(@code,@str,@indexb)-len(@code))
else
return right(@str,len(@str)-charindex(@code,@str,@indexb)-len(@code)+1)
end
return ''
END
(@str nvarchar(4000),@code varchar(10),@no int )
RETURNS varchar(200)
AS
BEGIN
declare @intLen int
declare @count int
declare @indexb int
declare @indexe int
set @intLen=len(@code)
set @count=0
set @indexb=1
if @no=0
if charindex(@code,@str,@indexb)<>0
return left(@str,charindex(@code,@str,@indexb)-1)
else
return @str
while charindex(@code,@str,@indexb)<>0
begin
set @count=@count+1
if @count=@no
break
set @indexb=@intLen+charindex(@code,@str,@indexb)
end
if @count=@no
begin
set @indexe=@intLen+charindex(@code,@str,@indexb)
if charindex(@code,@str,@indexe)<>0
return substring(@str,charindex(@code,@str,@indexb)+len(@code),charindex(@code,@str,@indexe)-charindex(@code,@str,@indexb)-len(@code))
else
return right(@str,len(@str)-charindex(@code,@str,@indexb)-len(@code)+1)
end
return ''
END
该文章转载自德仔工作室:http://www.dezai.cn/Article_Show.asp?ArticleID=17972&ArticlePage=2
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